PLAN AND CROSS SECTION FOR ISOLATED FOOTING
DETAILS FROM ABOVE DRAWING
- Length of Footing -x
- Breadth of footing - y
- Height of the footing -h (thickness)
- Dia of the main reinforcement bars- dm
- dia of distribution reinforcement bars- dd
- The spacing of reinforcement bars-
- cover - c
EXAMPLE
DETAILS OBTAINED FROM EXAMPLE
- Length of Footing -x =3m
- Breadth of footing - y=2.1m
- Height of the footing -h (thickness)=.35m
- Dia of the main reinforcement bars- dm=16
- dia of distribution reinforcement bars- dd=16
- The spacing of reinforcement bars- .150mm
- cover - c=50mm
Number of main bars =(X/Spacing of main reinforcement)+1
=(3/.15)+1
=21
Nos
B.
Calculation of number of distribution bars (distribution reinforcement)
Number of distribution bars =(y/Spacing of distribution reinforcement)+1
Number of distribution bars =(2.1/.15)+
Number of distribution bars =15
Nos
Number of distribution bars
=15*2= 30 nos (we have double mesh)
C.cutting length of
main bars (main reinforcement)
cutting length
of main bars =(Y-2Cover)+2(h-2cover)-2(2dm)
cutting length of main bars
=(2.1-2*.05)+2(.35-2*.05)-2(2*16)
cutting length of main bars
=2.436
Total
cutting length of main bars -2.436*42 =102.312
D.cutting length of
Distribution bars (distribution reinforcement)
A. cutting
length of distribution bars =(X-2Cover)+2(h-2cover)-2(2dd)
cutting length of distribution
bars =(3-2*.05)+2(.35-2*.05)-2(2*16)
cutting length of distribution
bars =3.336
Total
cutting length of distribution bars -3.336*30=100.08
E.STEEL QUANTITY CALCULATION
Weight = d2/162*total cutting
length
total weight of
main bars =(16*16/162)*102.312
total weight of main bars =161.67 Kg
total weight of distribution bars =(16*16/162)*100.08
total weight of distribution bars
=158.15 Kg
BAR BENDING SCHEDULE FOR ISOLATED FOOTING
Tags:
substructure